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MakcuM [25]
3 years ago
8

The wavelength of violet light in a spectrum is about 0.0000004 meters. which number best approximates this length as a power of

10
A. 4 x 10^-7
B. 4 x 10^-6
C. -4 x 10^7
D. 4 x 10^7
Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer:

Option A is correct.

Step-by-step explanation:

The wavelength of violet light in a spectrum is about 0.0000004 meters.

Now, we have to express this wavelength best approximate as a power of 10.

Now, 0.0000004 can be written as \frac{4}{10000000}

Therefore, 0.0000004 meters = \frac{4}{10^{7} } meters

So, 0.0000004 meters = 4 \times 10^{-7} meters

Hence, option A gives the correct answer. ( Answer )

Marysya12 [62]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

Hope this helps.

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The school is taking 80 students to the state fair for a field trip. There are students going from three different classes. Mr.
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If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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