What is the equation for the line with a slope of - 2/3 that passes through (0, -2)

Mathematics

1 answer:

viktelen [127]3 years ago

5 0

Answer:

y= -2/3x-2

Step-by-step explanation:

Since we have a point and a slope, we can use the point slope formula

$y-y_{1} =m(x-x_{1})$

m is the slope. In this case, m is -2/3

y1 is the y coordinate of the point. In this case, it is -2

x1 is the x coordinate. In this case it is 0.

We can substitute these values into the formula

y- -2= -2/3(x-0)

Distribute -2/3

y+2 = -2/3*x + -2/3*0

y+2= -2/3x+0

Subtract 2 from both sides. We want to get y by itself. This is because we want our line to be in y=mx+b form.

y+2-2= -2/3x+0-2

y= -2/3x -2

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daser333 [38]

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Daniel [21]

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Answer:

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