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ElenaW [278]
2 years ago
12

What is -23 over -46 simplified by?

Mathematics
2 answers:
Musya8 [376]2 years ago
6 0
0.5 as a fraction it is 1/5

That’s the answer!
Nostrana [21]2 years ago
3 0
This ggggggggbggvsg hhggg
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Would anyone help me with this,please ?
Novay_Z [31]

Answer:

angle 2 and 4....1and 3

Step-by-step explanation:

the lines bisects each other forming two equal but adjacent angles which are vertically opposite

8 0
2 years ago
Help me please please help
Dmitrij [34]

1) 8y + 9         2) 2n + 4        3) 3d + 5h

rearrange the equations and combine like terms. combine the terms with the same variables and add / subtract them.

for example number 1:

9y - 11 + 20 - y

is the same thing as

<em>9y - y</em> <u>+ 20 - 11</u>

and now you can easily combine them:

<em>8y</em> + <u>9</u>

i hope this helps!

4 0
3 years ago
Find the range of the following set of data:12,2,14,80,100
Leviafan [203]

Answer: 98

Step-by-step explanation: Subtract the biggest number from the smallest. 100-2=98

8 0
2 years ago
Read 2 more answers
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
2 years ago
What is the solutions of the equation 2 (x+2) ^2-4=28
JulsSmile [24]

Answer:

x = 2            x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

(x+2)^2 = 16

Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

x+2 = ±4

Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4      and x = -2-4

x = 2            x = -6

3 0
3 years ago
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