Answer:
pH = 7.46.
Explanation:
- The ionization of water is given by the equation :
<em>H₂O(l) ⇄ H⁺(aq) + OH⁻(aq),</em>
<em></em>
- The equilibrium constant (Kw) expression is:
<em>Kw = [H⁺][OH⁻] = 0.12 x 10⁻¹⁴. </em>
<em></em>
in pure water and neutral aqueous solution, [H⁺] = [OH⁻]
So, Kw = [H⁺]²
∴ 0.12 x 10⁻¹⁴ = [H⁺]²
∴ [H⁺] = 3.4 x 10⁻⁸ M.
∵ pH = - log [H⁺]
pH = - log (3.4 x 10⁻⁸) = 7.46.
1.75 x 104 is the correct answer
Answer : The volume required to administer a 75 mcg dose are, 0.75 mL
Explanation : Given,
Concentration of Digoxin = 0.1 mg/mL
That means, 0.1 mg of Digoxin present in 1 mL of solution.
Mass of dose = 75 mcg = 0.075 mg
Conversion used : (1 mcg = 0.001 mg)
Now we have to determine the volume required to administer a 75 mcg dose.
As, 0.1 mg of Digoxin required in 1 mL of solution
So, 0.075 mg of Digoxin required in
of solution
Thus, the volume required to administer a 75 mcg dose are, 0.75 mL
Ans: Elements in the same period have the same number of electron shells.