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MAXImum [283]
3 years ago
5

How many moles of chlorine are in 100g Chlorine (CI^2)?

Chemistry
1 answer:
Anni [7]3 years ago
4 0

Answer:

35.453 good luck with your work

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I need help pls this isnt chemistry btw i just couldnt find science so i had to put that
Elan Coil [88]

Answer: 1. 10% is used to live 30% is stored.

2. an educated guess.

Explanation:

3 0
2 years ago
43. A stock glucose standard has a concentration of 1,000 mg/dL. A 1/5 dilution of this standard is made. What would be the fina
Nat2105 [25]

The final concentration of the diluted standard is 0.2 mg/dL.

<h3 /><h3>What is concentration of glucose standard after 1/5 solution?</h3>

Using the dilution formula:

  • C1V1 = C2V2

where

  • C1 is initial concentration
  • V1 initial volume
  • C2 is final concentration
  • V2 is final volume.

Assuming a final volume of 100 mL, and since a 1/5 dilution is made:

C1 = 1.00 mg/dL

V1 = 20

C2 = ?

V2 = 100 mL

C2 = C1V1/V2

C2 = 20 × 1/100

C2 = 0.2 mg/dL

Therefore, the final concentration of the diluted standard is 0.2 mg/dL.

Learn more about dilution at: brainly.com/question/24881505

6 0
2 years ago
The balanced redox reactions for the sequential reduction of vanadium are given below.
Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)

2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)

On adding above equations, we get the following combined equation.

2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0
3 years ago
Can someone plss help me with this question!!
Ivahew [28]

Answer:

it is B because if u said A or D it would have been wrong and if u said C u would be going left.

Explanation:

7 0
3 years ago
Determine the theoretical maximum moles of ethyl acetate, , that could be produced in this experiment. The reactant, acetic acid
kherson [118]

Answer:

0.1832 moles of ethyl acetate (C_{4}H_{8}O_{2})

Explanation:

1. Find the balanced chemical equation:

In the production of ethyl acetate, the acetic acid CH_{3}COOH reacts with ethanol to produce ethyl acetate C_{4}H_{8}O_{2} and water, that is:

CH_{3}COOH+C_{2}H_{5}OH=C_{4}H_{8}O_{2}+H_{2}O

2. Find the theoretical maximum moles of ethyl acetate C_{4}H_{8}O_{2}:

As the problem says that the acetic acid CH_{3}COOH is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:

11gCH_{3}COOH*\frac{1molCH_{3}COOH}{60.05gCH_{3}COOH}*\frac{1molC_{4}H_{8}O_{2}}{1molCH_{3}COOH}=0.1832molesC_{4}H_{8}O_{2}

4 0
3 years ago
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