How many moles of chlorine are in 100g Chlorine (CI^2)?

I need help pls this isnt chemistry btw i just couldnt find science so i had to put that

Elan Coil [88]

Answer: 1. 10% is used to live 30% is stored.

2. an educated guess.

Explanation:

3 0

2 years ago

43. A stock glucose standard has a concentration of 1,000 mg/dL. A 1/5 dilution of this standard is made. What would be the fina

Nat2105 [25]

The final concentration of the diluted standard is 0.2 mg/dL.

<h3 /><h3>What is concentration of glucose standard after 1/5 solution?</h3>

Using the dilution formula:

C1V1 = C2V2

where

C1 is initial concentration
V1 initial volume
C2 is final concentration
V2 is final volume.

Assuming a final volume of 100 mL, and since a 1/5 dilution is made:

C1 = 1.00 mg/dL

V1 = 20

C2 = ?

V2 = 100 mL

C2 = C1V1/V2

C2 = 20 × 1/100

C2 = 0.2 mg/dL

Therefore, the final concentration of the diluted standard is 0.2 mg/dL.

Learn more about dilution at: brainly.com/question/24881505

6 0

2 years ago

The balanced redox reactions for the sequential reduction of vanadium are given below.

Minchanka [31]

Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

$2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)$ $2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)$

$2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)$

On adding above equations, we get the following combined equation.

$2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)$

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

$12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}$

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

$0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn$

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

$0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn$

We need 0.0392 grams of Zn metal to completely reduce vanadium.

6 0

3 years ago

Can someone plss help me with this question!!

Ivahew [28]

Answer:

it is B because if u said A or D it would have been wrong and if u said C u would be going left.

Explanation:

7 0

3 years ago

Determine the theoretical maximum moles of ethyl acetate, , that could be produced in this experiment. The reactant, acetic acid

kherson [118]

Answer:

0.1832 moles of ethyl acetate ( $C_{4}H_{8}O_{2}$ )

Explanation:

1. Find the balanced chemical equation:

In the production of ethyl acetate, the acetic acid $CH_{3}COOH$ reacts with ethanol to produce ethyl acetate $C_{4}H_{8}O_{2}$ and water, that is:

$CH_{3}COOH+C_{2}H_{5}OH=C_{4}H_{8}O_{2}+H_{2}O$

2. Find the theoretical maximum moles of ethyl acetate $C_{4}H_{8}O_{2}$ :

As the problem says that the acetic acid $CH_{3}COOH$ is the limiting reagent, use stoichiometry to find the moles of ethyl acetate produced:

$11gCH_{3}COOH*\frac{1molCH_{3}COOH}{60.05gCH_{3}COOH}*\frac{1molC_{4}H_{8}O_{2}}{1molCH_{3}COOH}=0.1832molesC_{4}H_{8}O_{2}$

4 0

3 years ago