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Free_Kalibri [48]
4 years ago
11

How do you work out? (step by step please) 2x-4≥6(x-1)

Mathematics
1 answer:
Tomtit [17]4 years ago
3 0
2x-4 \geq 6(x-1)\\\\ 2x-4 \geq 6x-6 \\\\ 2x-6x \geq -6+4 \\\\-4x \geq -2 \ |:(-2) \\\\ 2x \leq 1 \\\\ x \leq \frac{1}{2} \\\\ \boxed{x= (-\infty; \frac{1}{2} ] }
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Find the slope please using the formula
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Answer:

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Step-by-step explanation:

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Solve the equation 6x^2 + 15x + 3= 2x^2 to the nearest tenth.
Slav-nsk [51]

Answer:

x = -0.2 and x = -3.5

Step-by-step explanation:

Combine like terms in the given equation, by subtracting 2x^2 from both sides:

6x^2 + 15x + 3 = 2x^2

-2x^2                = -2x^2

----------------------------------

4x^2 + 15x + 3 = 0

This is a quadratic equation.  We'll find the two solutions using the quadratic equation

      -b ± √(b^2 - 4ac)

x = ---------------------------

                  2a

Here the coefficients of the quadratic are a = 4, b = 15 and c = 3.

Thus, the discriminant b^2 - 4ac is 15^2 - 4(4)(3), or +177

and from that we know we'll find two real, unequal roots.

                                -15 ± √177

The roots are:  x = ------------------- , or x = -0.2 and x = -3.5

                                         8

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