Which of the following expressions could be used to represent "the difference between -17 and -8"?

PLEASE HELP ASAP!!!!! a simulation by tossing a coin to model whether these puppies will be male or female. • Let heads (H) = fe

weeeeeb [17]

Answer:

7/10 or 70%

Step-by-step explanation:

There has to be at least two T in each result of the simulation. This means you can also have 3 T's and 4 T's in the result.

These are the results that qualify as having at least two T's.

1. TTTT, 2. TTTT, 3. THTH, 4. HTTT, 5. TTTT, 7. HTHT, 9. THTH

That is 7 out of the 10 results which is 7/10 or 70%

3 0

2 years ago

Plz I need some help this is a quick one and I'm having trouble focusing!

Ivenika [448]

Answer:

Juan:34

Kim:30

Larry:36

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

What is the measure of angle A, in degrees?

juin [17]

96°.

Since sides AB and AC ane equal, that means that angle B is equal to angle C. The measurement of all the angles of a triangle always equals 180°, so if you add angles B and C, you should get 84° and then you should be able to find angle A. Subtract 84° from 180° and you should get 96°.

8 0

4 years ago

1.

Eddi Din [679]

Answer:

a) $y=\dfrac{5}{2}x$

b) yes the two lines are perpendicular

c) $y=\dfrac{5}{4}x+6$

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form $y = mx + c$

$5y = 7 - 2x$

$y = \dfrac{7 - 2x}{5}$

$y = \dfrac{7}{5} - \dfrac{2}{5}x$

$y = -\dfrac{2}{5}x+\dfrac{7}{5}$

this is changed into the $y = mx + c$ , and we easily see that -2/5 is in the place of m, hence $m = \frac{-2}{5}$ is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

$m_1m_2=-1$ .

here both slopes $m_1$ and $m_2$ are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

$\dfrac{-2}{5}m_2=-1$ .

$m_2=\dfrac{5}{2}$ .

Finally, we can find the equation of the line of the perpendicular using:

$(y-y_1)=m(x-x_1)$

we know that the line passes through origin(0,0) and its slope is 5/2

$(y-0)=\dfrac{5}{2}(x-0)$

$y=\dfrac{5}{2}x$ is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether $m_1m_2=-1$ ?

the slopes can be easily found through rearranging both equations to $y=mx+c$

Line:1

$2x + 3y =6$

$y =\dfrac{-2x+6}{3}$

$y =\dfrac{-2}{3}x+2$

Line:2

$y = \dfrac{3}{2}x + 4$

this equation is already in the form we need.

the slopes of both equations are

$m_1 = \dfrac{-2}{3}$ and $m_2 = \dfrac{3}{2}$

using

$m_1m_2=-1$

$\dfrac{-2}{3} \times \dfrac{3}{2}=-1$

$-1=-1$

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be $m=\dfrac{-4}{5}$ and the y-intercept is $c=6$ the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.