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earnstyle [38]
4 years ago
9

Solve for x in the equation 3x^2 + 17x + 4 = -6

Mathematics
2 answers:
Sever21 [200]4 years ago
6 0
Subtract -6 from both sides
3x^2 + 17x + 4 - (-6) = -6 - (-6)
3x^2 + 17x + 10 = 0

factor left side of equation
(3x+2)(x+5)=0

set factors to 0
x = -2/3 OR x = -5

I would go with -5
Sphinxa [80]4 years ago
4 0

Answer:

x=-\frac{2}{3}\\ or\\x=-5

Step-by-step explanation:

3x^2+17x+4=-6

add 6 on both sides.

3x^2+17x+4+6=-6+6

3x^2+17x+10=0

Solve using the quadratic formula;

x=\frac{-b\frac{+}{}\sqrt{b^2-4ac}  }{2a}

a=3

b=17

c=10

---------------------------------------------------------------------------------------------

x=\frac{-(17)\frac{+}{}\sqrt{(17)^2-4(3)(10)}  }{2(3)}

x=\frac{-17\frac{+}{}\sqrt{289-120}  }{6}

x=\frac{-17\frac{+}{}\sqrt{169}  }{6}

x=\frac{-17\frac{+}{}13  }{6}

----------------------------------------------------------------------------------------------

x=-\frac{17}{6}+\frac{13}{6}\\x=-\frac{4}{6}\\ x=-\frac{2}{3}

or

x=-\frac{17}{6}-\frac{13}{6}\\x=-\frac{30}{6} \\x=-5

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