Answer:
The rectangle is 16*18
Step-by-step explanation:
The area of a rectangle is length * width and the perimeter is 2 times length * width
A = l*w
P = 2(l+w)
Replacing A and P
288 = l*w
68 = 2(l+w) => 34 = l+w => 34 - w = l
replacing l in the area
288 = (34 - w) w
w^2 - 34w + 288 = 0
(w - 16)(w - 18)
w = 16
w = 18
replacing in 34 - w = l
you get that when w = 16, l = 18 and when w = 18, l = 16
Answer:
A. 322 mm^2
Step-by-step explanation:
The area of the rectangle is 14 times 20
14 x 20 = 280
The area of the rectangle is 1/2 times 14 times 6
1/2(14)(6)=42
Finally add 280 and 42 and the answer is 322
I’m pretty sure it is B
Hope I helped.
Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
