She is wrong because 1and 1/3(2/6) + 1/6 = 1 and 3/6 or 1 and 1/2
Coach Smith is buying equipment for his soccer team. He has 11 players and each player needs three uniforms, two shin guards, one ball, and two pairs of cleats.
Part A: Write an algebraic expression to represent this situation.
Part B: If each uniform costs $48.00, each shin guard costs $5.00, each ball costs $17.00, and each pair of cleats costs $89.00, determine how much Coach Smith will spend, before taxes, on equipment for his soccer team.
PART A:
Let the cost of a uniform be a, that of a shin guard, b, that of a ball, c, and that of a pair of cleats, d, then
The algebraic expression representing the situation is given by
11(3a + 2b + c + 2d)
PART B:
The amount coach smith will spend is given by
11(3(48) + 2(5) + 17 + 2(89)) = 11(144 + 10 + 17 + 178) = 11(349) = $3,839
The answer should be B. you combine the like terms. when it is a negative sign in front of the parenthesis, when removing the parenthesis, every term inside the parenthesis need to change sign, negative to positive, positive to negative.
Answer:
m∠LNK = 86.8°
Step-by-step explanation:
∵ LH ⊥ KN at H
∵ LK = MN
∵ LM = 3
∴ HN = (13 - 3) ÷ 2 + 3 = 8 ⇒ isosceles trapezium
∵ LN = 89
∴ LH = √(89² - 8²) = 88.64
∵ KH = (13 - 3) ÷ 2 = 5 ⇒ isosceles trapezium
∵ tan ∠LKN = LH/KH = 88.64/5
∴ m∠LKN = 86.77° ≅ 86.8°