Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
<span>x^2 + 8x = -3
</span><span>x^2 + 8x + 16 = -3 + 16
using a^2 + 2 a b + b^2 = (a+b)^2
</span><span>
</span>x^2 + 8x + 16 = 13
<span>(x +4)^2 = 13
answer : 16 is the number </span><span>you must add to complete the square</span>
Answer:
x > 5
Step-by-step explanation:
3 ( 2x - 4 ) > 2 ( x + 4 )
6x - 12 > 2x + 8
4x > 20
x > 5
Answer:
21 + 3a
Step-by-step explanation:
3 (7+a)
distribute 3 into parentheses:
21 + 3a
Length is 48 ft
The perimeter of a rectangle is equal to the sum of all side’s.
2(lengths)+2(widths)= perimeter
Length=3x+4
Now given the perimeter of 140
3(3x+4)+3(x)=140
9x+12+3x=140
12x+12=140
12x=128
X= 10.7
10.7 is the width
Length=3x+4
Length =3(10.6)+4
Length=31.8+4
Length=35.8
Answer = 35.8
This can only be answered if you were given a perimeter.
