All categories

4 years ago

What equation this show The cost of 10 pounds of potatoes is 8 dollars

1 answer:

8 0

To formulate the equation that shows the cost of 10 pounds of potatoes is 8 dollars we proceed as follows;
suppose the cost 1 pound is x;
thus,
total cost=(amount in pounds)*(price of one pound)
total cost=$8
amount=10 pounds
cost of one pound=x
thus the equation is;
8=10x

You might be interested in

Imagine slicing the pyramid with a plane parallel to its base and passing through the topmost point of the pyramid. What will th

Nitella [24]

Answer:

Cross sections perpendicular to the base and through the vertex will be triangles. Below, you can see a plane cutting through the pyramid, part of the pyramid removed, and the cross section. You could also take a slice parallel to the base. Cross sections parallel to the base will be hexagons.

Step-by-step explanation:

6 0

3 years ago

Finding the expression

vekshin1

If you combine like terrms its easy, you just have to -5+5+6y, 6y=16 y=2.66666667

4 0

4 years ago

Maria deposited her pay check of $301.86 into her savings account that already had $123.16. She then withdrew $60.00 for her wee

stich3 [128]

Her new balance is -$8.42

8 0

3 years ago

Read 2 more answers

Jim, Dora, Ada, and Kim together placed a total of 60 cupcakes on a tray. Jim placed 0.45 of the cupcakes, Dora placed 10of the

Zigmanuir [339]

Jim- 60× .45= 27
Dora- 10 of the 60
Ada- 60× .25= 15
Kim- 8 remaining

Jim placed the most with 27

7 0

3 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

3 years ago