How long would it take to earn $1,000,000 if you invested $750000 $10%

If a number in powers-of-ten notation is written as just the number 10 and the exponent, what is assumed to be part of the numbe

ElenaW [278]

Well, in scientific notation, you have a decimal and the ×10 represents how much you go back. So for example:

00.000296599×10^-2

3 0

3 years ago

12 is 90% of what number?

vekshin1

.90x = 12
x = 12/.9 = 13 1/3
Hope this helps :D

8 0

3 years ago

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Consider the probability that at least 88 out of 153 registered voters will vote in the presidential election. Assume the probab

Liono4ka [1.6K]

Answer:

0.9319 = 93.19% probability that at least 88 out of 153 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

153 voters:

This means that $n = 153$

Assume the probability that a given registered voter will vote in the presidential election is 63%.

This means that $p = 0.63$

Mean and standard deviation:

$\mu = E(X) = np = 153(0.63) = 96.39$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.63*0.37} = 5.97$

Consider the probability that at least 88 out of 153 registered voters will vote in the presidential election.

Using continuity correction, this is: $P(X \geq 88 - 0.5) = P(X \geq 87.5)$ , which is 1 subtracted by the p-value of Z when X = 87.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{87.5 - 96.39}{5.97}$

$Z = -1.49$

$Z = -1.49$ has a p-value of 0.0681.

1 - 0.0681 = 0.9319

0.9319 = 93.19% probability that at least 88 out of 153 registered voters will vote in the presidential election.

5 0

2 years ago

Hey scale drawing of Jamy’s living room is 4cm in width and 6cm length. If each 2cm on the scale drawing equals 8 feet what are

igor_vitrenko [27]

2 cm = 8 feet.
4 / 2 = 2. 8 * 2 = 16. 16 feet in width.
Now, the length:
6 / 2 = 3. 8 * 3 = 24. 24 feet in length.
The actual dimensions are 16 feet in width and 24 feet in length.

5 0

3 years ago

How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Alla [95]

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

3 0

3 years ago

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