Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
<u>f(x) = = (x + √2 i) (x - √2 i) (x - 2 ) (x + 1)</u>
Step-by-step explanation:
The given function is f(x) = x⁴ - x³ -2x -4
factor the polynomial function
f(x) = x⁴ - x³ -2x -4 = (x⁴ - 4) - (x³ + 2x ) ⇒ take (-) as a common from (- x³ -2x)
= (x² + 2 ) (x² - 2) - x (x² + 2) ⇒ take (x² + 2) as a common
= (x² + 2 ) ( x² - x - 2)
= (x + √2 i) (x - √2 i) (x -2 ) ( x+1)
Notes: (x⁴ - 4) = (x² + 2 ) (x² - 2)
(x² + 2)= (x + √2 i) (x - √2 i)
( x² - x - 2) = (x -2 ) ( x+1)
1/2 of $8.50 is $4.25
1/4 of $4.20 is $1.05
$5.30 w/o taxes
$5.74 is your answer