Question

In humans, syndactyly (webbed digits) is inherited by possession of a dominant allele (S). If a man who is homozygous and normal digits (55) marries a woman who is heterozygous for syndactul and has webbed diaits, what percentage of their children would be expected to have webbed digits?

Answer 1

Answer:

The % of children with webbed digits is $50$%

Explanation:

Given -

Syndactyly or webbed digits are due to the presence of  a dominant allele (S). Then the allele for normal digits would be represented by allele "s"

A normal man with normal digits and genotype "ss" marries a woman with webbed digits and has a hetrozygous genotype i.e "Ss"

If we cross Ss and ss , then the following offspring are produced -

Ss * ss

Ss, Ss, ss, ss

Out of four 2 offspring with genotype ss have normal digits and remaining two offspring with genotype "Ss" have webbed digits. Thus, the % of children with webbed digits is $50$%