Nitrogen and hydrogen
N2 +3 H2 ---> 2NH3
hope that answers the question:)
Answer:
The direct conversion of mesenchymal tissue into bone is called i<u><em>ntramembranous ossification</em></u> .The process by which a cartilage intermediate is formed and replaced by bone cells is called <em>endochondral osssification.</em>
Explanation:
Intramembranous ossification is one of the two essential process during the fetal development of the gnathosome skeltal system by which rudimentary bone tissue is created. It is the process of bone development from fibrous membranes. It is involved in the formation of the flat bones of the skull, mandible and the clavicle. This type of ossification also helps in healing of bone fractures.
Endochondral Osssification: Method of forming a bone through cartilage intermediate. It is also involved in the formation of long bones.
Like a panic button, the amygdala issues an alert, summoning other parts of the brain that play a role in the experience of fear, one example would be your hypothalamus. Amygdala as stated is the center for emotions, emotional behavior and motivations.
What's a cone of depression?
O C. An area where the water table
slopes toward a well
Answer:
(a) 0.16
(b) 1
Explanation:
Let Probability that ticks in the Midwest carried Lyme disease, P(L) = 0.16
Probability that ticks in the Midwest carried HGE disease, P(H) = 0.10
Probability that ticks in the Midwest carried either Lyme disease or HGE disease, P(
) = 0.10
(a) Probability that a tick carries both Lyme disease (L) and HE (H) is given by
P(L 
H);
As we know that P(A 
B) = P(A) + P(B) - P(A B)
So, in our question;
P(L H) = P(L) + P(H) - P(L H)
0.10 = 0.16 + 0.10 - P(L H)
P(L H) = 0.16 + 0.10 - 0.10 = 0.16
Therefore, the probability that a tick carries both Lyme disease (L) and HE (H) is 0.16 or 16% .
(b) <em>Conditional Probability P(A/B) is given by</em> = 
So, the conditional probability that a tick has HE given that it has Lyme disease is given by = P(H/L)
P(H/L) = 
= 
= 1 .
