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ElenaW [278]
3 years ago
6

Classify the following triangle as acute, obtuse, or right.

Mathematics
1 answer:
kiruha [24]3 years ago
4 0

Answer:

A. Obtuse

F. Scalene

Step-by-step explanation:

<u>There are two ways to classify a triangle:</u>

by <u>angles</u>:

Obtuse - has one angle that is greater than 90°

Right - has one angle that is 90°

Acute - has all angles less than 90°

and by <u>side lengths</u>:

Equilateral - all sides are equal

Isosceles - two sides are equal

Scalene - no sides are equal

In this triangle, there is an obtuse angle (A. Obtuse).

∡ = 132°, which is greater than 90°.

There are no equal sides (F. Scalene).

6 ≠ 7 ≠ 11.9

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Halp
ValentinkaMS [17]

Answer:

D. None of the above.

Step-by-step explanation:

Supplementary angles must add up to 180 degrees.

Complementary angles must add up to 90 degrees.

Vertical angles are opposite of each other.

Hope this helps!

If not, I am sorry.

5 0
2 years ago
What is <br> 1.5 repeated as a fraction
Andru [333]
1 and 1/2 is the answer 
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4 years ago
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A recipe calls for 2 cups of milk for each batch of pancakes. Jamie would like to triple her recipe. How many cups of milk will
Arturiano [62]
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4 years ago
Allan writes down n positive integers so that the sum of those numbers is 23. When he multiples those numbers, he gets the maxim
Inga [223]

Answer:

  • 3, 3, 3, 3, 3, 3, 3, 2

Step-by-step explanation:

To get maximum product we need to optimize how we break down the numbers

Its obvious we don't want number 1 to be used as it won't change the product

Also we don't want to use big numbers, we can have four 5's instead of two 10's as it would give greater product, 5*5 > 10

<u>What is best number?</u>

  • 2 and 3 are the smallest, 4 can be written as two 2's
  • 5 = 2+ 3 and 2*3 = 6, so it is better to use 2's and 3's instead of 5
  • 6 = 2+2+2, 2^3 = 8 and 6 = 3+ 3, 3^2 = 9, so it is better to use two 3's for 6
  • 7 = 2+2+3, 2*2*3= 12, again 2's and 3's make greater product

<u>So the best is to break the number down to 2's and 3's</u>

  • 23 = 2*10 + 3 ⇒ 2^10*3 = 3072
  • 23 = 3*7 + 2 ⇒ 3^7*2 = 4374

As we see the maximum product we can get is 4374 with seven 3's and one 2.

<u>Hence the numbers are:</u>

  • 3, 3, 3, 3, 3, 3, 3, 2

8 0
3 years ago
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Convert 4.7 into an improper fraction.
Lerok [7]
4 7/10 is the answer 

6 0
3 years ago
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