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Pie
3 years ago
8

Line p and q are are perpendicular. If the slope of line m is 2 what is the slope of line q

Mathematics
1 answer:
jeka943 years ago
3 0

slope line of q= -1/2

perpendicular slopes are those that are opposite sign and reciprocal to the given slope

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In one lottery game, contestants pick five numbers from 1 through 23 and have to match all five for the big prize (in any order)
mihalych1998 [28]

The probability of matching three out of five numbers is 153/33649

<h3>How to determine the probability?</h3>

The numbers are given as:

1 to 23

There are five matching numbers

The  probability of getting a match is:

p = 5-k/n where k = 0, 1, 2

While the complement probability is

q = (n - 2)/n

Using the above formulas, the probability of getting from 5 is:

P = 5/23 * 4/22 * 3/21 * 18/20 * 17/19

Evaluate the product

P = 153/33649

Hence, the probability of matching three out of five numbers is 153/33649

Read more about probability at:

brainly.com/question/14290572

#SPJ1

6 0
2 years ago
Which is equivalent to the series shown?
garri49 [273]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
PLZ HELP ME I BEG YOU !!!!!!!!!!!!!!
Zigmanuir [339]
3x200= 600
1000-600=400
400 divided by 5 = 80
answer is 80 adults

can u mark me brainliest?
3 0
3 years ago
Solve for x help don't know how to do this
Charra [1.4K]
Both triangle are isosceles, which means their base angles are congruent.

54 + 2y = 180
2y = 126
y = 63 

The measure of the base angles of the triangle on the left is 63 degrees.

180 - 63 = 117

117 + 2x = 180
2x = 63
x = 31.5

Answer:
x = 31.5

Hope this helps.
5 0
4 years ago
A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0
3 years ago
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