The probability of matching three out of five numbers is 153/33649
<h3>How to determine the probability?</h3>
The numbers are given as:
1 to 23
There are five matching numbers
The probability of getting a match is:
p = 5-k/n where k = 0, 1, 2
While the complement probability is
q = (n - 2)/n
Using the above formulas, the probability of getting from 5 is:
P = 5/23 * 4/22 * 3/21 * 18/20 * 17/19
Evaluate the product
P = 153/33649
Hence, the probability of matching three out of five numbers is 153/33649
Read more about probability at:
brainly.com/question/14290572
#SPJ1
Answer:
please I don't know
Step-by-step explanation:
please I don't know
please give me another question
3x200= 600
1000-600=400
400 divided by 5 = 80
answer is 80 adults
can u mark me brainliest?
Both triangle are isosceles, which means their base angles are congruent.
54 + 2y = 180
2y = 126
y = 63
The measure of the base angles of the triangle on the left is 63 degrees.
180 - 63 = 117
117 + 2x = 180
2x = 63
x = 31.5
Answer:
x = 31.5
Hope this helps.
Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.