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swat32
4 years ago
13

Write an expression for the nth term of... 2,1,0,-1...

Mathematics
1 answer:
Drupady [299]4 years ago
7 0

Answer:

a_{n} = 3 - n

Step-by-step explanation:

There is a common difference between consecutive terms in the sequence, that is

1 - 2 = 0 - 1 = - 1 - 0 = - 1

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = - 1 , thus

a_{n} = 2 - 1(n - 1) = 2 - n + 1 = 3 - n

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4 years ago
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Given:-

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The conjucate is,

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Now we simplify. so we get,

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Substituting the value -1. we get,

\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{                               =}\frac{6-4+11i}{2+1} \\ \text{                              =}\frac{2+11i}{3} \end{gathered}

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