Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
f(4) = 6
Step-by-step explanation:
f(x) = 3x - 6
f(4) = 3(4) - 6
f(4) = 12 - 6
f(4) = 6
840 is the answer
i hope i helped!
Hey there!!
The area for the volume of a cube -
s³ , s = side
volume = 216
s³ = 216
s = ∛216
s = 6
The required answer is 6
Hope my answer helps!
Answer:I don’t know either
Step-by-step explanation:
