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3 years ago

13

The amount of gasoline remaining on the tank decreases with mileage driven. Identify the independent and dependent quantity in t

he situation.

2 answers:

artcher [175]3 years ago

6 0

mileage driven;amount of gasoline remaining in the tank

never [62]3 years ago

3 0

Independent is the gasoline amount and dependent is the mileage driven

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63 is 90% of what number? using double number lines to get the answer

iren2701 [21]

Since the 90% is 63. divide it by 9. then you would get value of 7. then multiple it by 10.
which is equal to 70. so 100% is 70.

7 0

3 years ago

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Is this correct? please do let me know honestly.

Wittaler [7]

Answer:

You're correct.

5 0

2 years ago

Which equation is equivalent to √x^2+81 = x+10

jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

$\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2$

By definition: $(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2$

$x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100$

Thus, $x ^ 2 + 81 = x ^ 2 + 20x +100$ is equivalent to $\sqrt {x ^ 2 + 81} = x + 10$

Answer:

$x ^ 2 + 81 = x ^ 2 + 20x +100$

Option D

4 0

4 years ago

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Solve the inequality

exis [7]

N<6 is the answer I think

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3 years ago

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The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula

Semmy [17]

Answer:

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

$V=\frac{4}{3} \pi r^{3}$

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

$V=\frac{4}{3} \pi r^{3}$ ......Given

$3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}$

Therefore,

$r=\sqrt[3]{\frac{3V}{4\pi }}$

is the required r

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3 years ago