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3 years ago

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The amount of gasoline remaining on the tank decreases with mileage driven. Identify the independent and dependent quantity in t

he situation.

2 answers:

artcher [175]3 years ago

6 0

mileage driven;amount of gasoline remaining in the tank

never [62]3 years ago

3 0

Independent is the gasoline amount and dependent is the mileage driven

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The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the

MA_775_DIABLO [31]

Answer:Let's assume x be the smaller number.

Given that, The greater number is 4 more than the smaller number.

So, greater number= x+4.

It's also given that, The sum of two numbers is 52. Which means sum of x and x+4 must be equa to 52. Hence,

x + (x + 4) = 52

Step-by-step explanation:

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2 years ago

Find the value of x.

alukav5142 [94]

Step-by-step explanation:

The sum of the three angles in a triangle must be $180$ . Since this triangle has a right angle, we know that it is $90$ °, so the sum of the remaining two angles must be $90$ .

We can set up an equation for the two remaining angles to determine the value of $x$ :

$(x + 28) + x = 90$

$2x + 28 = 90$

$2x = 62$

$x = 31$

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3 years ago

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5(8n+ 7) < 5-5(n+3)

svet-max [94.6K]

Answer:

n<-1

Step-by-step explanation:

Distribute 5 and -5 into each parenthesis respectively: 40n+35<5-5n-15

Combine like terms: 40n+35<-5n-10

Add 5n to both sides: 45n+35<-10

Subtract 35 from both sides: 45n<-45

Divide both sides by 45: n<-1

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3 years ago

Which could be the function graphed below?

Lina20 [59]

Answer:A

Step-by-step explanation:

if you look at it carefully the endpoint is at the bottom of the Y value which looks like negative 2 this is the only answer you can be

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3 years ago

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

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2 years ago