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vodka [1.7K]
3 years ago
11

4. Written as the product of two binomials, the expression (x+3)(4x –1)-(x+3)(x –9) is

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

Step-by-step explanation:

(x+3)(4x-1)=4x^2+11x-3

(x+3)(x-9)=x^2-6x-27

if we add both binomials we will get=3x^2+17x+24

the expression in this case is a binomial

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Find the solution of 64 = 16u algebraically.<br> please I’m desperate
Sauron [17]

Answer:

u = 4

Step-by-step explanation:

Divide by 16 on both sides. [Division Property of Equality]

64/16 = 16u/16

u = 4

==================================================================<em>Hope I Helped, Feel free to ask any questions to clarify :) </em>

<em> Have a great day! </em>

<em> More Love, More Peace, Less Hate. </em>

<em>      -Aadi x</em>

3 0
3 years ago
Charlie's weight is nine kilograms greater than his brother's. Together they weigh 99 kilograms. Let x represent the weight of t
spayn [35]
C=x+9, c+x=99, c=99-x

So we have two equations equal to c, c=x+9 and c=99-x, since c=c:

x+9=99-x

2x+9=99

2x=90

x=45, and since c=x+9, c=54

So Charlie weighs 54 kg and his brother weighs 45 kg.
4 0
4 years ago
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
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Step-by-step explanation:

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C.L.T

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quester [9]

Answer:

nothing is wrong with it

Step-by-step explanation:

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3 years ago
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