the diagonals PR and QS of a rhombus intersect each other at point O. prove that 2(PQ) + 2(RS) + 2(RS)+ 2(PS) = 4 (2(OP)+2(OQ))
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Answer:
20 percent
Step-by-step explanation:
Total number of pieces in a puzzle = 500
No. of pieces in first container = 220
No. of pieces in second container = 180
Let no. of pieces in the third container be x.
We get,
On adding 220 and 180, we get
On transposing 400 to RHS, we get
Percentage of pieces in the third container = (no. of pieces in third container/total no. of pieces in a puzzle)
Therefore, percentage of pieces in the third container = 20 percent