3 years ago

the diagonals PR and QS of a rhombus intersect each other at point O. prove that 2(PQ) + 2(RS) + 2(RS)+ 2(PS) = 4 (2(OP)+2(OQ))

1 answer:

3 0

Answer:

6 is the answer

Step-by-step explanation:

You might be interested in

n200080 [17]

Answer:

Step-by-step explanation:

because your more likely to open to a page deeper in the magazine

5 0

3 years ago

lianna [129]

Answer:

244

Step-by-step explanation:

74+42=116

360-116=244.

5 0

3 years ago

vodka [1.7K]

Answer:

y+2= -4(x-8)

Step-by-step explanation:

6 0

2 years ago

Alexeev081 [22]

$1.3 per lemon. I divided 8 by $6 and got 1.3.

3 0

3 years ago

Hoochie [10]

3 but in most cases it is 2 real roots and one root has a multiplicity of 2

5 0

3 years ago