Answer:
Rate = k[aryl halide][nucleophile]
Explanation:
The simple aryl halides are almost inert to usual nucleophilic reagents but considerable activation on the ring can be produced by the addition of strongly electron-attracting substituents on either the ortho or para positions, or both. These groups deactivate the ring to allow the attack of the nucleophille on the ring.
Thus, these reactions can occur by following addition-elimination mechanism in which the nucleophille first attacks the aryl halide and then the elimination of the leaving group takes place.
<u>Kinetic studies of this type of mechanism demonstrate that the reactions are of second-order kinetics– first order w.r.t. nucleophile and also, first-order w.r.t. aromatic substrate. The rate determining step (r.d.s.) is the formation of the addition intermediate.</u>
Thus,
<u>Rate = k[aryl halide][nucleophile]</u>
#21
- initial velocity=u=5m/s
- Time=t=2s
- Acceleration=a=1.3m/s²
According to first equation of kinematics
- v=u+at
- v=5+1.3(2)
- v=5+2.6
- v=7.6m/s
#22
#a
- v1=2+3(3)=2+9=11m/s
- v2=-8-4(3)=-20m/s
- v3=1-5(3)=-14m/s
The order is
#b
for speed find absolute velocity
- S1=|11|=11m/s
- S2=|-20|=20m/s
- S3=|-14|=14m/s
So order is
S1<S3<S2
"K+" is the one metal ion among the choices given in the question that produces <span>the light with the highest energy. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that the answer has actually come to your help.</span>
Answer:
a) 
b) 
c) 
d) 
Explanation:
a) The initial vertical velocity is given by:
Where:
θ: 25°
v: is the magnitude of the speed = 23 m/s
b) The initial horizontal velocity can be calculated as follows:
c) The flight time can be calculated using the following equation:
Where:
x: is the total distance = 42 m
d) The maximum height is given by:
Where:
: is the final vertical velocity =0 (at the maximum heigth)
g: is the gravity = 9.81 m/s²
I hope it helps you!
