Answer:
<h2>2940 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 245 × 12
We have the final answer as
<h3>2940 J</h3>
Hope this helps you
Answer:
Check the explanation
Explanation:
This is the step by step explanation to the above question:
![v_i = v [ f_L *(v - v_b) - f_s*(v + v_b)] / [f_L * (v - v_b) + f_s*(v +v_b)]](https://tex.z-dn.net/?f=v_i%20%3D%20v%20%5B%20f_L%20%2A%28v%20-%20v_b%29%20-%20f_s%2A%28v%20%2B%20v_b%29%5D%20%2F%20%5Bf_L%20%2A%20%28v%20-%20v_b%29%20%2B%20f_s%2A%28v%20%2Bv_b%29%5D)
= v * (83.1 * (v-4.3) - 80.7 ( v+4.3))/ [83.1 *(v - 4.3) + 80.7*(v + 4.3)]
v = 344 m/s
vi = 344 * ( 83.1* (344-4.3) - 80.7*(344+4.3) ) / (83.1 *(344 - 4.3) + 80.7*(344 + 4.3))
= 0.74 m/s
Answer: 6.36
Explanation:
Given
Radius of grindstone, r = 4 m
Initial angular speed of grindstone, w(i) = 8 rad/s
Final angular speed of the grindstone, w(f) = 12 rad/s
Time used, t = 4 s
Angular acceleration of the grinder,
α = Δw / t
α = w(f) - w(i) / t
α = (12 - 8) / 4
α = 4/4 = 1 rad/s²
Number of complete revolution in 4s =
Δθ = w(i).t + 1/2.α.t²
Δθ = 8 * 4 + 1/2 * 1 * 4²
Δθ = 32 + 1/2 * 16
Δθ = 32 + 8
Δθ = 40 rad/s
40 rad/s = 40/2π rpm = 6.36 rpm
Therefore, the grindstone does 6.36 revolutions during the 4 s interval
If the measurement is in joules then you can push something or pull something as long as you are moving the object. Formula: f*n force times newtons
Answer:
Hello friend where is the figure of the question