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4 years ago

Solve for k. 6 + -4k = 18 k=

Mathematics

1 answer:

Harlamova29_29 [7]4 years ago

4 0

Answer: K = -3

Step-by-step explanation:

subtract 6

-4k =12

divide 12 by -4 to get k by itself

k= -3

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Free points, please solve -2m+36=2(6m-3)?

Elan Coil [88]

Answer:

$\Huge \boxed{m=3}$

Step-by-step explanation:

$-2m+36=2(6m-3)$

Expanding brackets.

$-2m+36=12m-6$

Adding 2m and 6 to both sides.

$36+6=12m+2m$

Combining like terms.

$42=14m$

Dividing both sides by 14.

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3 years ago

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prisoha [69]

Answer:

Your answer would be 1.8 miles.

Step-by-step explanation:

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3 years ago

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The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

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We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

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3 years ago

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Tcecarenko [31]

Answer:

Step-by-step explanation:

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Answer:

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3 years ago