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Angelina_Jolie [31]
3 years ago
9

The density of lead is greater than iron, and both metals are denser than water. Is the buoyant force on a solid lead object (a)

greater than, (b) equal to, or (c) less than the buoyant force acting on a solid iron object of the same dimensions?
Physics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

b) equal

Explanation:

in question we it is given that the density of the iron is greater than the density of lead and the density of the water is less than both  the metal.

As both the body is submerged in the water so for the buoyant force calculation  we will take the density of water.

i.e. for buoyant force calculation both the metal will have equal buoyant force acting on it.

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A pitot tube system measures the static pressure in 50 cm diameter duct containing air (\rho\:=rho =1.1 kg/m3) as 97 kPa and the
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Answer:

The velocity in duct is 73.854 m/s.

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Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 \frac{kg}{m^{3} }.

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Using Bernoulli equation,

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When air is flowing through duct,

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v^{2}=5454.54

v=73.854 m/s.

Therefore, The velocity in duct is 73.854 m/s.

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