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Hatshy [7]
3 years ago
6

Fill in the blanks to complete each statement about energy in Earth’s crust. (use lower case wording only)

Physics
2 answers:
miv72 [106K]3 years ago
8 0

Answer:

stress and fault

Explanation:

yes

Naetoosmart
2 years ago
you have to add the s at the end of faults
Fiesta28 [93]3 years ago
7 0

Answer:

Stress for the first one and the second faults

Explanation:

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Trial and error

scientific laws and theories are proven by experimental data and large bodies of evidence.
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The specific heats of aluminum and iron are 0.214 and 0.107 calories per gram degrees Celsius​ [cal/(g degrees Upper C ​)] respe
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Answer:

Answer for question "

The specific heats of aluminum and iron are 0.214 and 0.107 calories per gram degrees Celsius​ [cal/(g degrees Upper C ​)] respectively. If we add the same amount of energy to a cube of each material​ (of the same​ mass) and find that the temperature of the aluminum increases by 28 degrees Fahrenheit ​[degrees Upper F ​], how much will the iron temperature increase in degrees Fahrenheit ​[degrees Upper F ​]? "

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4 years ago
What is renewable and non-renewable energy?​
Greeley [361]

Renewable resources:

A renewable resource is one that can be used repeatedly and does not run out because it is naturally replaced.

Nonrenewable resource:

A nonrenewable resource is a natural substance that is not replenished with the speed at which it is consumed. It is a finite resource.

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4 0
3 years ago
Read 2 more answers
A wheel of radius 0.38 m rotates in a clockwise sense about a fixed axle with negligible friction at an initial angular speed of
andrew-mc [135]

Answer:

ωf = 2.19 rad/s

Explanation:

Newton's second law:

F = ma has the equivalent for rotation:

τ = I * α   Formula  (1)

where:

τ : It is the torque applied to the body.  (Nxm)

I :  it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Data

F = 24 N  : Tangential force

m : 14 kg : mass of the wheel

R = 0.38 m : radius of the wheel

Moment  of inertia of  the wheel

The moment of inertia of wheel is defined as follows:

I = m* R²

I = 14 kg*(0.38)²

I = 2.0216 kg*m²

Torque applied to the wheel

The Torque ( τ) applied to the wheel is defined as follows:

τ = F*d

Where:

F : Tangential force applied to the wheel

d : Perpendicular distance of the tangential force to the axis of rotation

τ = (24N)*(0.38 m)

τ = 9.12 N*m

Angular acceleration of the wheel  (α )

We replace data in the formula (1):

τ = I * α

9.12 = (2.0216) * α

α= 9.12 / (2.0216)

α = 4.5 rad/s²  

Kinematics of the wheel

We apply the equations of circular motion uniformly accelerated :  

ωf = ω₀ + α*t Formula (2)

Where:  

α : Angular acceleration (rad/s²)  

ω₀ : Initial angular speed ( rad/s)  

ωf : Final angular speed ( rad

t : time interval (s)

Data  

α = 4.5 rad/s²  

ω₀ =1.6 rad/s

t =  0.13 s    

We replace data in the formula (2):  

ωf = ω₀ + α*t

ωf = 1.6 + (4.5)*(0.13)

ωf = 1.6 + (4.5)*(0.13)

ωf = 2.19 rad/s

6 0
3 years ago
Imagine that you have obtained spectra for several galaxies and have measured the observed wavelength of a hydrogen emission lin
Anna71 [15]

Answer:

Galaxy 1:

z = 0.0056

Galaxy 2:

z = 0.014

Galaxy 3:

z = 0.040

Explanation:

Spectral lines will be shifted to the blue part of the spectrum¹ if the source of the observed light is moving toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect). The source in this particular case is represented for each of the galaxies of interest.

Hence, the redshift represents this shift of the spectral lines to red part in the spectrum of a galaxy or any object which is moving away. That is a direct confirmation of how the universe is in an expanding accelerated motion.

The redshift can be defined in analytic way by means of the Doppler velocity:

v = c\frac{\Delta \lambda}{\lambda_{0}}  (1)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

v = c(\frac{\lambda_{measured}-\lambda_{0}}{\lambda_{0}})

\frac{v}{c} = \frac{\lambda_{measured}-\lambda_{0}}{\lambda_{0}}  

z = \frac{\lambda_{measured}-\lambda_{0}}{\lambda_{0}}  (2)

Where z is the redshift.

<em>For the case of Galaxy 1: </em>

Where \lambda_{measured} = 660.0 nm and \lambda_{0} = 656.3 nm.

z = \frac{\lambda_{measured}-\lambda_{0}}{\lambda_{0}}

z = (\frac{660.0 nm - 656.3 nm}{656.3 nm})

z = 0.0056

<em>For the case of Galaxy 2: </em>

Where \lambda_{measured} = 665.8 nm and \lambda_{0} = 656.3 nm.

z = \frac{665.8 nm - 656.3 nm}{656.3 nm}

z = 0.014

<em>For the case of Galaxy 3:</em>

       

Where \lambda_{measured} = 682.7 nm and \lambda_{0} = 656.3 nm.

z = \frac{682.7 nm - 656.3 nm}{656.3 nm}

z = 0.040

Key terms:

¹Spectrum: Decomposition of light in its characteristic colors (wavelengths).

8 0
3 years ago
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