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Anastaziya [24]
2 years ago
14

1. Why should you use scientific notation when writing big numbers?

Physics
1 answer:
Fynjy0 [20]2 years ago
6 0

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

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Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel
kenny6666 [7]

Explanation:

Given that,

Two resistors 4.5 Ω and 2.3 Ω .

Potential difference = 30 V

When they are in series, the current through each resistor remains the same. First find the equivalent resistance.

R' = 4.5 + 2.3

= 6.8 Ω

Current,

I=\dfrac{V}{R'}\\\\I=\dfrac{30}{6.8}\\\\=4.41\ A

So, the current through both lightbulb is the same i.e. 4.41 A.

When they are in parallel, the current divides.

Current flowing in 4.5 resistor,

I_1=\dfrac{V}{R_1}\\\\=\dfrac{30}{4.5}\\\\I_1=6.7\ A

Current flowing in 2.3 ohm resistor,

I_2=\dfrac{V}{R_2}\\\\=\dfrac{30}{2.3}\\\\I_2=13.04

In parallel combination, are brighter than bulbs in series.

5 0
3 years ago
What is the purpose of a kink in a thermometer?
AnnZ [28]

Answer:

A 'kink' in the glass tube which breaks the mercury as it contracts, storing the highest temperature reading. The glass tube is shaped like a lens to magnify the thin mercury thread. Shaking the thermometer resets the mercury back into the bulb.

3 0
2 years ago
Read 2 more answers
Two everyday examples of a starting motion
Tasya [4]
Pushing, pulling is the answer
8 0
3 years ago
Ntally Check for Understanding
Wewaii [24]

Answer: 34

Explanation:

34

3 0
2 years ago
Calculate the acceleration of a 1000 kg car if the motor provides a small thrust of 1000 N and the static and dynamic friction c
grin007 [14]

Explanation :

It is given that,

Mass of the car, m = 1000 kg              

Force applied by the motor, F_A=1000\ N

The static and dynamic friction coefficient is, \mu=0.5

Let a is the acceleration of the car. Since, the car is in motion, the coefficient of sliding friction can be used. At equilibrium,

F_A-\mu mg=ma

\dfrac{F_A-\mu mg}{m}=a

a=\dfrac{1000-0.5(1000)(9.81)}{1000}

a=-3.905\ m/s^2

So, the acceleration of the car is -3.905\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
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