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3 years ago

Ian factored 12x3y3 – 24x2y3 into 6xy(2x2y2 – 4xy2).

2 answers:

6 0

A. 6xy(2x^2y^2-4xy^2) If you need to multiply 6xy and 2x^2y^2 & 6xy and 4xy^2. You will get 12x^3y^3-24x^2y^3. b. Factorization is not complete because 6xy is not the greatest common factor. c. Complete factor: 12x^2y^3(x-2y).

Alenkinab [10]3 years ago

5 0

Answer:

Step-by-step explanation:

Given that Ian factored

$12x^3y^3 - 24x^2y^3$

$6xy(2x^2y^2 - 4xy^2).$

We find that inside still there are common factors for the two terms.

We can find 2 as common factor and for x, the term x and for y it is y^2

So correct factorisation would be

$12x^2y^3(x-2)$

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