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ICE Princess25 [194]
3 years ago
5

Ian factored 12x3y3 – 24x2y3 into 6xy(2x2y2 – 4xy2).

Mathematics
2 answers:
jonny [76]3 years ago
6 0
A. 6xy(2x^2y^2-4xy^2) If you need to multiply 6xy and 2x^2y^2 & 6xy and 4xy^2. You will get 12x^3y^3-24x^2y^3. b. Factorization is not complete because 6xy is not the greatest common factor. c. Complete factor: 12x^2y^3(x-2y).
Alenkinab [10]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that Ian factored

12x^3y^3 - 24x^2y^3

as

6xy(2x^2y^2 - 4xy^2).

We find that inside still there are common factors for the two terms.

We can find 2 as common factor and for x, the term x and for y it is y^2

So correct factorisation would be

12x^2y^3(x-2)

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4 years ago
Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5
abruzzese [7]

Answer:

The answer is <em>1</em>.

Step-by-step explanation:

Given the expression:

|z-6|-|z-5|,\ if\ z

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

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value is -x if x is negative

Here the given expression contains two absolute value functions:

|z-6| and |z-5|

Using the definition of absolute value function as per above definition.

|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z

|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression |z-6|-|z-5|,\ if\ z will be equivalent to :

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Answer:

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Step-by-step explanation:

<u>Given:</u>

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