Answer:
5:9
Step-by-step explanation:
1/5kg:360g
kg to g
1kg=1000g
1/5kg=1/5x1000
=200g
200g:360g
200g/360g
200/360
5/9
5:9
Answer:
5n + 12
Step-by-step explanation:
Perform the indicated multiplication. Then combine like terms:
2n + 3n + 12 = 5n + 12 (answer)
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
The bear beats its heart 50/6 times a minute during deep hibernation.
Thats 12 times a minute
45minutes x 12 times a minute
45x12 = 540
Answer: 540 times
Answer:
1.28 or 128
Step-by-step explanation:
you would take 32 and divide it by.25
