12.73 GB total when rounded to the nearest 100th.
3.5/27.5=y
y•100= 12.73
Answer: The zeroes are -2/3 and 4
Step-by-step explanation: The factored form you get from this is (3x+2) and (x-4), set these equal to 0. x-4=0 and 3x+2=0.
1) Graph the corresponding equation \( x = 2 \); this will split the plane into two regions. One of the region represents the solution set.
2) Select a point situated in any of the two regions obtained and test the inequality. If the point selected is a solution, then all the region is the solution set. If the selected point is not a solution, then the other (second) region represents the solution set.
3) Test: In this example, let us for example select the point with coordinates (3 , 2) which is in the region to the right of the line x = 2. If you substitute x in the inequality \( x ≥ 2 \) by 3 it becomes \( 3 ≥ 2 \) which is a true statement and therefore (3 , 2) is a solution. Hence, we can conclude that the region to the right of the vertical line x = 2 is a solution set including the line itself which is shown as a solid line because of the inequality symbol \( ≥ \) contains the \( = \) symbol. The solution set is represented by the blue hash region in the graph below including the line x = 2.
corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color c)the marbles are different in color
Answer:
Step-by-step explanation:
<u><em>The probability was done with replacement.</em></u>
Probaility of an event happening
number of blue marbles= 2
number of green marbles=5
total number of marbles=7
(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)


(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)



(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)


