A point that is half way of line segment is the midpoint
Let (6, 7) be (x₁, y₁) and (-7, -6) be (x₂, y₂)
Mid point of HI = (
)
Mid point of HI = (
Mid point of HI = (
)
Santiago's statement is not correct
Answer:
where is the question?
Step-by-step explanation:
Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm
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Below are the answers:
<span>7. C. H(n) = ½n^2 + n + 1
</span>8. D. As the number of rows increases, the hexagonal rig gets closer to having twice as many lights as the square rig.
Step-by-step explanation:
Mean= Sumof all the numbers/ number of data
So,
23+37+11+58+13+45=187
Now...
187/6=31.166666667 Answer
hope it helps....
