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Solnce55 [7]
3 years ago
9

If there is a $50 profit on the large cabinets and a $30 profit on the small cabinets.

Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer: B

Step-by-step explanation: I hope I am good at math if not sorry

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Solve for h.<br><br> –2 − 10h = –11h − 20
Delvig [45]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

-2 - 10h = -11h - 20

+ 2

- 10h = -11h - 18

+ 11h

h = -18

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5 0
3 years ago
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How I do this someone ples help I need help with 25 and 27.
marta [7]

Number 15 is no solution.

Number 27 is that x has to be between -2 or 2.

This could be explained as -2≤x≤2

8 0
3 years ago
Need help with this math lesson
Naya [18.7K]

-9(-4)  /  4 - (-2)

= -9*-4 / 4 + 2

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6 0
3 years ago
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Nu is designing a rectangular sandbox.The bottomm is 16 square feet.Which dimensions require the least amount of materail for th
zzz [600]

Given Information:  

Area of rectangle = 16 square feet

Required Information:  

Least amount of material = ?

Answer:

x = 4 ft and y = 4 ft

Step-by-step explanation:

We know that a rectangle has area = xy and perimeter = 2x + 2y

We want to use least amount of material to design the sandbox which means we want to minimize the perimeter which can be done by taking the derivative of perimeter and then setting it equal to 0.

So we have

xy = 16  

y = 16/x

p = 2x + 2y

put the value of y into the equation of perimeter

p = 2x + 2(16/x)

p = 2x + 32/x

Take derivative with respect to x

d/dt (2x + 32/x)

2 - 32/x²

set the derivative equal to zero to minimize the perimeter

2 - 32/x² = 0

32/x² = 2

x² = 32/2

x² = 16

x = \sqrt{16} = 4 ft

put the value of x into equation xy = 16

(4)y = 16

y = 16/4

y = 4 ft

So the dimensions are x = 4 ft and y = 4 ft in order to use least amount of material.

Verification:

xy = 16

4*4 = 16

16 = 16 (satisfied)

7 0
3 years ago
Every prime number has greater than 10 has a digit in the ones place that is included in which set of numbers below?
kompoz [17]
Its 1379 and 137 that what i think
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