Your answer for y would be 2.
18/9=2.
Answer:
= 14q
Step-by-step explanation:
21q - 7q
= 14q
(3q - p) (7)
= 21q - 7q
= 14q
Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³
The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³
Now, the number of boxes that can fit in the cargo hold of the truck will be,
Number of boxes = (Volume of truck container)/(Volume of box)
= 843.75/15.625
= 54
Hence, the number of boxes that can fit in the cargo hold of the truck is 54.
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Answer:
The answer is D
Step-by-step explanation:
first you have to find the same denominator
the denominator will be 30 because 5×6=30 same with 6×5=30
and whatever you do to the bottom you do to the top so 4×6=24 and 7×5= 35
so its 35/30- 24/30= 11/30 so 7/6-4/5=35/30-24/30 is 11/30=11/30 which is correct.
Problem 1
y = tan(3x+4)
f(x) = tan(3x+4)
f ' (x) = 3sec^2(3x+4) .... apply derivative chain rule
dy/dx = f ' (x)
dy = f ' (x) * dx
dy = ( 3sec^2(3x+4) ) * dx
Now plug in x = 5 and dx = 0.3
dy = ( 3sec^2(3*5+4) ) * 0.3
dy = 0.920681 which is approximate
Make sure your calculator is in radian mode. Calculus textbooks will be in radian mode for the special sine limit definition
to be true.
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Problem 2
We'll have the same derivative function and same x value. The only difference is that dx = 0.6 this time.
dy = f ' (x) * dx
dy = ( 3sec^2(3*5+4) ) * 0.6
dy = 1.84136 approximately