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murzikaleks [220]
3 years ago
14

Seven times a number is 28 more than three times that number​

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

x=7

Step-by-step explanation:

The sentence can be rewritten as: (Replace "a number" with X)

7x=3x+28

1) Subtract a 3x from both sides:

4x=28

2) Divide both sides by 4:

x=7

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Miranda buys 6 pounds of nuts. If she puts 1/5 pounds in each bag, how many bags can she make?
Brrunno [24]
30 bags: each pound can make 5 bags (1/5) so 6 x 5 = 30
3 0
3 years ago
Calculate the answer to the correct number of significant digits. (91.01)(10.7)
aalyn [17]

Answer:

974

Step-by-step explanation:

(91.01)*(10.7)

91.01*(10.7)

91.01*10.7

973.80700

974

6 0
3 years ago
you own seven travel books and are taking five of them on vacation. in how many ways can you select the five books you will take
Ipatiy [6.2K]
It depends on how many options you have
You multiply the total number of books you have time 5 because you can choose 5
8 0
3 years ago
Which of the following is a proportion?
poizon [28]

Answer:

Option C, 14/21=9/21 is the proportion.

Step-by-step explanation:

Given:

a.5/7 = 10/12

b.9/15 = 12/18

c.4/6 = 8/12

d.14/21 = 9/12

We have to find the proportions.

In proportion two ratios are equal, as it has an equality sign in between so both side must be of same ratio in its simplest form.

Let's work with option C

⇒ \frac{4}{6}=\frac{8}{12}

To find the simplest form we have to divide the numerator and denominator with same digit (or its factor).

Simplest form of  \frac{8/2}{12/2} = \frac{4}{6} , \frac{4/2}{6/2}= \frac{2}{3}

Simplest form of \frac{4}{6} = \frac{2}{3}

Both sides in option C have equal ratios of 2/3.

So 4/6=8/12 is in proportion.

6 0
3 years ago
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
Read 2 more answers
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