Hello here is a solution :
<span> the radius of the circle is OA A(5;-12) and O (0;0)
OA= </span><span> square root ((5-0)² + (-12-0)²)
</span> = <span> square root (25+144)
</span> = <span> square root(169)
</span> OA = 13
Step-by-step explanation:
from difference of two squares:
therefore:
factorise out ¾ :
Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Since y=5 is an asymptote, it means that y will approach 5 but never be 5. So you use (. Then, you see the function increasing from the asymptote so it would be (5, infinity) Choice C
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