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beks73 [17]
3 years ago
13

Simplify. (3.8w+ 4) – 1.5w+8 2.3 w+ 12 5.3 w+ 12 2.3 w-12 5.3 w-12

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

2.3w+12

Step-by-step explanation:

Parentheses do not matter for this question.

(3.8w+ 4)–1.5w+8=

3.8w+4-1.5w+8=

<em>Subtract 1.5w from 3.8w</em>

2.3w+4+8=

<em>Add 4 and 8 together</em>

2.3w+12

Artyom0805 [142]3 years ago
4 0

Answer:

2.3w +12

Step-by-step explanation:

(3.8w+ 4) – 1.5w+8

Combine like terms

3.8w-1.5w   +4+8

2.3w +12

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1) Two circles are concentric if they have the same center and different radii.

2) The equation of a circle with center xc, yc, and radius r is:

(x - xc)^2 + (y - yc)^2 = r^2.

So, if you have that equation you can inmediately tell the coordinates of the center and the radius of the circle.

3) You can transform the equations given in your picture to the form (x -xc)^2 + (y -yc)^2 = r2 by completing squares.

Example:

Equation: 3x^2 + 3y^2 + 12x - 6y - 21 = 0

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complete squares: (x + 2)^2 - 4 + (y - 1)^2 - 1 = 7

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equation: 4x^2 + 4y^2 + 16x - 8y - 308 = 0

rearrange: 4x^2 + 16x + 4y^2 - 8y = 308

common factor 4: 4 (x^2 + 4x) + 4(y^2 -8y) = 4*77

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complete squares: (x + 2)^2  - 4 + (y - 1)^2 - 1 = 77

=> (x + 2)^2 + (y - 1)^2 = 82 => center = (-2,1), r = √82

Therefore, you conclude that these two circumferences have the same center and differet r, so they are concentric.
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