Answer:
d
Step-by-step explanation:
Step-by-step explanation:
Using Pythagoras' identity on the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
AB² = 7² + 4² = 49 + 16 = 65 ( take the square root of both sides )
AB = \sqrt{65} → D
Answer:
See below
Step-by-step explanation:
I assume you mean 
:
Holes: Since reduces to 
, then there is a hole at 
as 
exists in both the numerator and denominator (however, its limit as x approaches 0 is 1/5).
Vertical Asymptotes: If we further reduce to 
, then we see that there are vertical asymptotes at 
and 
Horizontal Asymptotes: As the degree of the numerator is less than the degree of the numerator (
), then there is a horizontal asymptote at 
