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mina [271]
3 years ago
7

Which of the following sampling techniques is the most likely to produce a random sample, representative sample of all students

at a high school?
A. Choosing every 10th name on the student roster
B. Choosing every 10th student arriving in a 9th grade homeroom
C. Choosing the first 100 students who arrive at school
D. Asking students to call a phone number to answer survey questions
Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer:

Which of the following sampling techniques is the most likely to produce a random sample, representative sample of all students at a high school?

A. Choosing every 10th name on the student roster

B. Choosing every 10th student arriving in a 9th grade homeroom

<u>C. Choosing the first 100 students who arrive at school </u>

D. Asking students to call a phone number to answer survey questions

Step-by-step explanation:

Ray Of Light [21]3 years ago
3 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ A. choosing every 10th name on the student roster.

This is the most random as it is non biased. The first and second one are biased towards the student who arrive early and therefore, wouldn't produce a random sample. The last one is also not random as it relies on volunteers.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Solve the following systems b elemination show work and explain each step 3x + y = 13 4x - 3y = 13
Alika [10]

Answer:

x = 4

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Step-by-step explanation:

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3x + y = 13

4x- 3y = 13

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5 0
2 years ago
LT1 10th grade level
Anton [14]

Answer:

The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = \overline{EF}/\overline{BC}

Step-by-step explanation:

From the question diagram, we have two triangles, ΔEAF and ΔABC;

The ratio of the lengths of the sides \overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC}

∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC

Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar

Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal

We have;

\overline{AE}/\overline{AB} =  \overline{FA}/\overline{AC} = 50 ft. /(100 ft.) =  \overline{EF}/\overline{BC} = \overline{EF}/120 ft.

\overline{EF} = 120 ft. × 50 ft./(100 ft.) = 60 ft.

\overline{EF} = 60 ft.

The distance between the pirate and the treasure, \overline{EF} = 60 ft.

4 0
3 years ago
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