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mart [117]
3 years ago
7

PLLLEAASE HELLPfghjkjhgfdfghjk

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
Since AB and BC are congruent, ABE is equivalent to CBE. ABE+CBE=ABC. So the answer would be 80 degrees.
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Two gears are connected and are rotating simultaneously. The smaller gear has a radius of 3 inches, and the larger gear has a ra
Dovator [93]
Circumference of a circle is C = 2πr.

part 1)

so the radius of the smaller gear is 3 inches, so after a full rotation, namely a revolution, the smaller gear has covered an arc of 2π(3), or 6π.

what angle has the larger gear of 7 inches in radius, has it covered with an arc of 6π?

\bf \textit{arc's length}\\\\
s=r\theta ~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=6\pi \\
r=7
\end{cases}\implies 6\pi =7\theta \implies \cfrac{6\pi }{7}=\theta



part 2)

since the larger gear has a radius of 7, in a revolution it will have an arc of 2π(7), or 14π.

now, we know the smaller gear does a 6π arc in a revolution, how many revolutions will it do in an arc of 14π?

\bf \begin{array}{ccll}
arc&revolution\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
6\pi &1\\
14\pi &x
\end{array}\implies \cfrac{6\pi }{14\pi }=\cfrac{1}{x}\implies \cfrac{3}{7}=\cfrac{1}{x}\implies x=\cfrac{7}{3}
6 0
3 years ago
Fifty balls numbered 1 through 50 are mixed up in a barrel. How many balls must you draw from the barrel (without looking) to be
ipn [44]
If you draw only 25 balls, you could draw the 25 odd-numbered balls.  However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls.  Thus, the minimum is 25+2=27 balls.
8 0
3 years ago
Mark has a checking account. His opening balance on 1/7 was $110. The bank charges a 25¢ fee for each debit card transaction and
ipn [44]
110+30-(15+0.25)+40-(8+0.25)=156.5
7 0
2 years ago
Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

8 0
3 years ago
Sub tract 13/15 -1/5
Arada [10]
It would be .6 repeating
6 0
2 years ago
Read 2 more answers
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