3 years ago

PLLLEAASE HELLPfghjkjhgfdfghjk

Mathematics

1 answer:

vodka [1.7K]3 years ago

3 0

Since AB and BC are congruent, ABE is equivalent to CBE. ABE+CBE=ABC. So the answer would be 80 degrees.

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The pirce of an item yesterday was$125 . Today, the price fell to 75. Find the percentage decrease.

Julli [10]

Answer:

Im sure the answer is 40%

GL Deary

Hope I helped!!!

<3

8 0

4 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

What are the intercepts of f(x)=x^2

dusya [7]

C. It is a basic parabola

7 0

3 years ago

Triangle PQR has vertices (0, 4), (2, 5), and (3, 8).

marishachu [46]

Answer: the answer should be B

7 0

3 years ago

4. The mean of the data 2, 3, 4, 5, 0, 1, 3, 3, 4, 3 is a. 2 b. 2.2 C. 2.4 d. 2.8

arsen [322]

Answer:

its 2•8

u add all together then divide it number of times e.g 2+3+4+5+0+1+3+3+4+3=28

so 28/10= 2•8

4 0

3 years ago

Read 2 more answers