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Kaylis [27]
3 years ago
5

Need help with 5 and/or 6

Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:

ok

Step-by-step explanation:

not really hard if you concentrate

right now check the curve and see if you'll see x axis

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What is the product of the binomials (4a – 1) and (2b + 3)?
galben [10]

Answer:

D. 8ab+12a-2b-3

Step-by-step explanation:

You are basically combining like terms

8 0
3 years ago
Read 2 more answers
Place value of 0 1 4 3 6 9 in 987,164.302
Blizzard [7]
0 is in the hundredths place
1 is in the hundreds place
4 is in the ones place
3 is in the tenths place
6 is in the tens place
9 is in the hundred-thousands place
3 0
3 years ago
If f(x) = 3^x + 10x and g(x) = 2x - 4, find (f + g)(x)
allsm [11]

Answer:

3^x + 12x -4

Step-by-step explanation:

f(x) = 3^x + 10x

g(x) = 2x - 4,

(f + g)(x) = 3^x + 10x +  2x - 4

Combine like terms

             = 3^x + 12x -4

6 0
3 years ago
Read 2 more answers
5.676524687 in fraction
Ugo [173]

Answer:

5 7/10

Step-by-step explanation:

First, we need to round the number.

5.7

Now that we've rounded the number we can convert it to a fraction based on where the decimal is located.

5.7

   |

   v

Tenths

So, the decimal is in the tenths that means we have to put 7 over 10.

5 7/10

Hope this helps! :)

6 0
3 years ago
Solve the following equation:<br> a) 3x - 9 = 27/ 1 - 5x<br> b) 10x - 1/x = 3
mars1129 [50]

Answer:

A) x=9/2 B) x=-1/5, 1/2

Step-by-step explanation:

3x-9=27/1-5x

3x-9=27-5x

3x-(-5x)-9=27

3x+5x-9=27

8x-9=27

8x=27+9

8x=36

x=36/8

simplify

x=9/2

Answer: x=9/2

-----------------------------

10x-1/x=3

(10x^2-1)/x=3

10x^2-1=3*x

10x^2-1=3x

10x^2-3x-1=0

factor out the trinomial,

find two numbers that when they multiply,

you get the third term, which is -1 in this case.

When you add those 2 numbers, you get the second term,

which is -3 in this case.

(5x+1)(2x-1)=0

apply the zero property from here,

set 5x+1=0 and 2x-1=0 and solve for x.

5x=0-1=-1, x=-1/5,

2x=0+1=1, 2x=1, x=1/2.

So x=-1/5, 1/2.

5 0
3 years ago
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