Answer:
a

b

Explanation:
Considering question a
From the question we are told that
The mass of the rocket is
The mass of the fuel which is in the rocket is m = 0.6 M
Generally given that the rocket burns all it fuel in a single stage , the final velocity of the rocket is mathematically represented as
![v_f = v_{ex} ln [\frac{m_o}{m_k} ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_%7Bex%7D%20%20ln%20%5B%5Cfrac%7Bm_o%7D%7Bm_k%7D%20%5D)
Here
is the mass of the rocket without fuel which is mathematically evaluated as

=> 
=> ![m_k = [1- 0.6] m_o](https://tex.z-dn.net/?f=m_k%20%3D%20%20%20%5B1-%20%200.6%5D%20m_o)
=>
=> 
Considering question b
From the question we are told that
The mass of the fuel it burn at the first stage is 
The mass of the first stage fuel tank 
The mass of the fuel at the second stage is 
Generally the velocity of the rocket at the first stage is mathematically represented as
![v_i = v_{ex} * ln [ \frac{m_o }{[1- m]m_o } ]](https://tex.z-dn.net/?f=v_i%20%3D%20v_%7Bex%7D%20%2A%20ln%20%5B%20%5Cfrac%7Bm_o%20%7D%7B%5B1-%20m%5Dm_o%20%7D%20%5D)
=> ![v_i = v_{ex} * ln [ \frac{m_o }{[1- 0.3]m_o } ]](https://tex.z-dn.net/?f=v_i%20%3D%20v_%7Bex%7D%20%2A%20ln%20%5B%20%5Cfrac%7Bm_o%20%7D%7B%5B1-%200.3%5Dm_o%20%7D%20%5D)
=>
=> 
Generally the mass of the rocket after first stage is

=> 
Generally the final velocity of the rocket at the second stage is
![v_f = v_i + v_{ex} * ln [\frac{m_r}{ m_f } ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20v_%7Bex%7D%20%2A%20ln%20%5B%5Cfrac%7Bm_r%7D%7B%20m_f%20%7D%20%5D)
=> ![v_f = v_i + v_{ex} * ln [\frac{0.6 m_o }{0.3mo } ]](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20v_%7Bex%7D%20%2A%20ln%20%5B%5Cfrac%7B0.6%20m_o%20%7D%7B0.3mo%20%7D%20%5D)
=> 
=> 
Answer:
C. valence electrons
Explanation:
Each dot is a valence electron.
Also, in my school, we called them Lewis Dot Structures.
Answer: D
Neither A nor B
Explanation:
In order to check the clearances for rod and main bearings, you need a set of micrometers and a dial-bore gauge
Measuring the inside diameter of a main or rod bearing will require a dial bore gauge. The best ones to use are accurate down to 0.0001-inch.
So, both technician A and B are incorrect
Solid because the particles vibrate in place