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kakasveta [241]
3 years ago
11

1. A 12kg mass is sliding down a ramp at a 30° angle from the horizontal. The coefficient of friction between the

Physics
1 answer:
eimsori [14]3 years ago
6 0

Answer:

101.8 N

Explanation:

To find the normal force acting on the mass, we just need to study the situation along the direction perpendicular to the plane.

There are only two forces acting along this direction:

- The normal force on the box, N, out of the inclined plane

- The component of the weight perpendicular to the plane, in the opposite direction, of magnitude

mg cos \theta

where

m = 12 kg is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

\theta=30^{\circ} is the angle of the ramp

The mass is in equilibrium along this direction, so the equation of motion is

N-mg cos \theta = ma = 0

Since the acceleration is zero: a = 0.

Therefore, we can now solving the equation to find N, the normal force:

N=mg cos \theta = (12)(9.8)(cos 30^{\circ})=101.8 N

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Trevor skis down a hill at a speed of 25 m/s. Friction slows him down to a
Burka [1]

Answer:

A. Diagram A

Explanation:

3 0
3 years ago
He sees a mouse sniffing along at 0.2 m/s but it hears and starts to scurry for safety. In just 4.7 s it speeds up to 1.6 m/s. F
NISA [10]

Answer:

0.30 m/s²

Explanation:

Given:

v₀ = 0.2 m/s

v = 1.6 m/s

t = 4.7 s

Find: a

a = (v − v₀) / t

a = (1.6 m/s − 0.2 m/s) / 4.7 s

a = 0.30 m/s²

8 0
4 years ago
At what distance along the z-axis is the electric field strength a maximum?
Lesechka [4]
The axial field is the integration of the field from each element of charge around the ring. Because of symmetry, the field is only in the direction of the axis. The field from an element ds in the ring is 

<span>dE = (qs*ds)cos(T)/(4*pi*e0)*(x^2 + R^2) </span>

<span>where x is the distance along the axis from the plane of the ring, R is the radius of the ring, qs is the linear charge density, T is the angle of the field from the x-axis. </span>

<span>However, cos(T) = x/sqrt(x^2 + R^2) </span>

<span>so the equation becomes </span>

<span>dE = (qs*ds)*[x/sqrt(x^2 + R^2)]/(4*pi*e0)*(x^2 + R^2) </span>

<span>dE =[qs*ds/(4*pi*e0)]*x/(x^2 + R^2)^1.5 </span>

<span>Integrating around the ring you get </span>

<span>E = (2*pi*R/4*pi*e0)*x/(x^2 + R^2)^1.5 </span>

<span>E = (R/2*e0)*x*(x^2 + R^2)^-1.5 </span>

<span>we differentiate wrt x, the term R/2*e0 is a constant K, and the derivative is </span>

<span>dE/dx = K*{(x^2 + R^2)^-1.5 +x*[(-1.5)*(x^2 + R^2)^-2.5]*2x} </span>

<span>dE/dx = K*{(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5} </span>

<span>to find the maxima set this = 0, giving </span>

<span>(x^2 + R^2)^-1.5 - 3*x^2*(x^2 + R^2)^-2.5 = 0 </span>

<span>mult both side by (x^2 + R^2)^2.5 to get </span>

<span>(x^2 + R^2) - 3*x^2 = 0 </span>

<span>-2*x^2 + R^2 = 0 </span>

<span>-2*x^2 = -R^2 </span>

<span>x = (+/-)R/sqrt(2) </span>
4 0
4 years ago
What happens to a light ray if it is incident on a reflective surface along the normal?
Bad White [126]

Answer: The incident ray and the reflected ray and the normal will be parallel to each other.

Explanation:

The normal is perpendicular to the surface of the mirror or the reflective surface.

According to the law of reflection which state that:

The angle of incidence is always equal to the angle of reflection on a smooth surface.

If a light ray is incident on a reflective surface along the normal. The angle of incidence will be at 90 degrees which will be perpendicular to the surface of the mirror, the reflected ray will bounce back likewise at the same angle which will be perpendicular to the reflective surface.

Both the incident ray and the reflected ray and the normal will be parallel to each other.

4 0
3 years ago
9. Which of the following statements is true about scientific theories?
AleksAgata [21]
I think the correct answer from the choices listed above is option D. Scientific theories summarize patterns found in nature. Although, the statement scientific theories are never proven is somewhat true. They are either disproved or they are never disproved. Hope this answers the question.
6 0
3 years ago
Read 2 more answers
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