Answer:
W = F * s
Work done equals applied force * distance traveled
Apparent weight = M g (1 - sin θ) since some of applied force will lighten sled
μ = coefficient of kinetic friction
F cos θ = force applied to motion of sled
s = distance traveled
[μ M g (1 - sin θ)] cos θ * s = work done in moving sled
Note that F = μ M g if applied force is in the horizontal direction
Answer:
m/s^2
Explanation:
Force = mass × acceleration
kgm/s^2 = kg × acceleration
where acceleration = Force ÷ mass
= kg m/s^2 ÷ kg
:Acceleration = m/s^2
The answer is false because there are single celled organisms.
Answer:
Explanation:
Magnitude of force per unit length of wire on each of wires
= μ₀ x 2 i₁ x i₂ / 4π r where i₁ and i₂ are current in the two wires , r is distance between the two and μ₀ is permeability .
Putting the values ,
force per unit length = 10⁻⁷ x 2 x i x 2i / ( 6 x 10⁻³ )
= .67 i² x 10⁻⁴
force on 3 m length
= 3 x .67 x 10⁻⁴ i²
Given ,
8 x 10⁻⁶ = 3 x .67 x 10⁻⁴ i²
i² = 3.98 x 10⁻²
i = 1.995 x 10⁻¹
= .1995
= 0.2 A approx .
2 i = .4 A Ans .
Answer:
33.65°
Explanation:
radius, r = 53.1 m
m = 2.9 Mg = 2.9 x 10^6 g = 2900 kg
v = 67 km/h
convert km/h into m/s
v = 18.61 m/s
Let the angle of banking of road is θ, without friction


tan θ = 0.6655
θ = 33.65°
Thus, the angle of banking of road is 33.65°.