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3 years ago

9

a piece of iron with a temperature of 300 degrees Celsius is dropped into a gallon of water with a temperature of 25 degrees Cel

sius heat will?

1 answer:

notka56 [123]3 years ago

7 0

Heat will be transferred from iron to water, because heat flows always from the higher temperature system to the lower temperature system.

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If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. Wha

Olegator [25]

Answer:

<h2>500m</h2>

Explanation:

Using the equation of motion S = ut + 1/2 gt²

S = the vertical displacement (in m)

u = initial velocity of the object (in m/s)

g = acceleration due to gravity (in m/s²)

t = time taken (in secs)

Given u = 0m/s, g = 10m/s² and t = 10s, substituting this value into the equation to get the vertical displacement w have;

S = 0+1/2 (10)(10)²

S = 1000/2

S = 500m

The vertical displacement after 10seconds is 500m

5 0

3 years ago

Hello, I need help. Due right now

ryzh [129]

Answer: See below

Explanation:

$\\ \mathrm{Given:} \\\mathrm{Mass \ of \ first \ car}$\left(m_{1}\right)=1383 \mathrm{~kg}$ \\ Velocity $\left(\overrightarrow{V_{1}}\right)=-11.2\ {\math} \mathrm{m} / \mathrm{s}$\\ Mass of second car -$\left(m_{2}\right)=1732 \mathrm{~kg}$\\ Velocity $\left(\vec{v}_{2}\right)=31.3 {\math} \mathrm{m} / \mathrm{s}$$

$m_{1} \vec{v}_{1}+m_{2} \vec{v}_{2}=\left(m_{1}+m_{2}\right) \vec{v} \\1383(-11.2 {\math})+1732(31.3 {\math}) \\=(1383+1732) \vec{v} \\-15489.6 {\math}+54211.6 {\math}=3115 \vec{v} \\ \vec{v}=(17.4 {\math}-4.972 {\math}) \ \mathrm{m/s}$

$\text { So magnitude } \vec{|v|} =\sqrt{(17.4)^{2}+(-4.972)^{2}} \\ =\sqrt{327.605} \\ =18.099 \mathrm \ {m/s} \\$

$\text { Direction } \\\theta=\tan ^{-1}\left(\frac{-4.972}{17.4}\right) \\\theta=-15.945^{\circ}\end{gathered}$

Therefore, both cars move with a velocity of 18.099 m/s in the direction of 15.945° downward from the x-axis (east)

7 0

3 years ago

Read 2 more answers

Ca+ is an example of a(n)

umka21 [38]

Answer:

Calcium

hope this helped mah dude :>

3 0

3 years ago

CH4 + 2O2 → CO2 + 2H2O The number in front of a compound in a balanced chemical equation is known as a(n) A) charge. B) coeffici

Tamiku [17]

The numbers in front of a compound is called a subscript. It shows how many atoms of that specific element it is next two that is involved in the reaction or is in that compound.

The answer is then D.

Coefficient is found behind the compounds, the charges are written above.

6 0

3 years ago

Calculate the amount of heat needed to increase the temperature of 200 grams of water at 10°C to 95°C.

Alexus [3.1K]

the amount of heat need is 71060 Joules

Explanation

The equation for the amount of heat needed to increase the temperature of water is as follows:

$\begin{gathered} E=mC(T_2-T_1) \\ where \\ \\ \end{gathered}$

where E is the amount of heat

C is the specific heat capacity of water having a standard value of 4180 J/kg*K

T is the final ans initial temperature in kelvin

m is the mass

so

Step 1

given

$\begin{gathered} mass=m=200\text{ gr=0.2 kg} \\ T_1=10\text{ \degree C} \\ T_2=95\text{ \degree C} \\ C=4180\text{ J/kh*K} \end{gathered}$

a) convert the temperature into kelvin

$\begin{gathered} 10\text{ \degree C=\lparen10+273\rparen K=283 K} \\ 95\text{ \degree C=\lparen95+273 \rparen K=368 K} \end{gathered}$

now, replace in the formula

$\begin{gathered} E=mC(T_{2}-T_{1}) \\ E=0.2\text{ kg*4180L/kg*K*\lparen368K-283 k\rparen} \\ E=71060\text{ J} \end{gathered}$

therefore, the amount of heat need is 71060 Joules

I hope this helps you

7 0

1 year ago

Read 2 more answers