Just before the ball leaves her hand, what is its centripetal acceleration?

We say that visible light has wavelength from 400nm to roughly 800nm. What is the biggest "energy-jump" (excited) for an atom if

icang [17]

Answer:

$4.98\cdot 10^{-19} J$

Explanation:

The energy of the emitted photon is inversely proportional to its wavelength, according to the equation:

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34} Js$ is the Planck's constant

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

This means that the biggest energy is released when the wavelength is the shortest. For a photon of visible light, the shortest wavelength is

$\lambda=400 nm = 400\cdot 10^{-9} m$

So, substituting into the equation, we find the corresponding energy:

$E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.98\cdot 10^{-19} J$

6 0

4 years ago

A copper ball and an aluminum ball of mass 150 g each are heated to 100°C and then cooled to a temperature of 20°C. The heat los

nevsk [136]

The specific heat of aluminum is actually simply a diversion. Because we can directly compute for the specific heat of copper using the formula:

ΔH = m C ΔT

where ΔH is change in enthalpy or heat lost, m is mass, C is specific heat and ΔT is change in temp

4,600 J = 150 g * C * (100 °C - 20°C)

C = 0.38 J/g°C

8 0

3 years ago

Read 2 more answers

What is a period on the periodic table?<br><br> a row<br><br> a column

docker41 [41]

Answer:

A row is a period on the periodic table.

4 0

3 years ago

A calorimeter is a container that is insulated from the outside, so a negligible amount of energy enters or leaves the container

Len [333]

Answer:

This is a heat balance question with negligible heat losses to the surroundings.

Sum of heat losses = Sum of the heat gains

We are required to find the final temperature of the calorimeter system T1?

we were given

C = specific heat capacities of Copper c, Water w, Ice i and Lead l

m = masses as mc = 0.1kg, mw = 0.16kg, mi=0.018kg, ml=0.75kg,

T = Temperature of the components, Lead Tl= 225C and at ambient pressure, Temp. To of the water, ice and copper = 25C

Since, at thermal equilibrium after adding the Lead, the lead temperature Tl decreases while copper, water and ice temp decrease, so we have respective heat losses 'q' as,

qc + qw + qi + ql =0

which means that

(mc x Cc x ΔTC) + (mw x Cw x ΔTC) + (mi x Ci x ΔTC) + (ml x Cl x ΔTC) = 0

(0.1x390x (T1 - 25)) + (0.16x4190x (T1 - 25)) + (0.018x4190x (T1 - 0)) + (0.750x130x (T1 - 225)) = 0

882.32T1 - 41558 = 0

T1 = 47.1K

Hence, the final temperature of the calorimeter system is 47.1K

3 0

4 years ago

Cuestionario:

Sati [7]

Explanation:

1.El objetivo principal de realizar la llamada entrada en calor o calentamiento, es preparar el cuerpo para la actividad física o deportiva. Numerosas lesiones y ciertos problemas cardíacos como algunas arritmias, están asociados a la ejercitación violenta sin mediar un adecuado calentamiento.

3 0

3 years ago