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Lubov Fominskaja [6]
2 years ago
9

How has florida contributed to america’s space race?.

Physics
1 answer:
astra-53 [7]2 years ago
5 0

Answer:

Florida's Cape Canaveral was central to the US victory in the space race. An isolated air force base was in Cape Canaveral near the ocean. This location allowed NASA scientists to test rockets freely.

Explanation:

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What gas law looks at the relationship between pressure and temperature of a gas? A) Boyle's Law B) Charles' Law C) Gay Lussac's
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Answer: it should be Boyle’s law

Explanation:

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Rewire each of the following using the correct prefix using 2 decimal places where applicable.
Ede4ka [16]

Answer:

a. 1.2×10^-6

b. 0.42×10^9

c. 246.8×10^3

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1:What kind of energy does your body use to keep you warm.
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1. thermal energy

2. Batteries and coal

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A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou
Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

\Delta KE = - \Delta PE

KE_t + KE_r = mgh

We know as well that the lineal and angular energy are given by,

KE_r = \frac{1}{2}I\omega^2

And the tangential kinetic energy as

KE_t = \frac{1}{2} mv^2

Where\omega = \frac{v}{R}

Replacing

\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh

Re-arrange for v,

v=\sqrt{\frac{2mgh}{m+I/R^2}}

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

I_{hp}=mR^2

v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}

v_{hp}=\sqrt{\frac{2mgh}{m+m)}

v_{hp}=\sqrt{gh}

For solid cylinder:

I_{sc}=\frac{1}{2}mR^2

v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}

v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}

v_{sc}=\sqrt{\frac{3}{4}gh}

For solid sphere,

I_{ss}=\frac{2}{5}mR^2

v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}

v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}

v_{ss}=\sqrt{\frac{10}{7}gh}

Then comparing the speed of the three objects we have:

v_{hp}

\sqrt{gh}

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4 years ago
In what ways are earth and a bar magnet alike?
xenn [34]
One way is the both have magnetic fields.
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