Short Answer:Choice C [Third one down]
RemarkStart with the number so I can talk about the basic principle at work. The way to work it is to factor 162 into prime factors and hope there are at least 3 that are the same.
162 = 2 * 81
162 = 2 * 3 * 3 * 3 * 3
Now When you take the cube root of that, you get
![\sqrt[3]{2*2*2*2*3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2%2A2%2A2%2A2%2A3%7D%20)
Here's the rule for a cube root. For every 3 prime factors under the cuberoot sign, you take out one and throw the other two away. So for cube root of 81,
you would factor it as ∛(81) = ∛(3 * 3 * 3 * 3) = 3∛3.
So out of four 3s under the cube root sign, you have 1 outside the root sign and one inside the root sign. 2 of the four 3s have been thrown away.
Continuation.X firstYou want 2 xs outside the root sign
∛(x * x * x * x * x *x ) = (x * x) You have thrown away 2 xs for every x outside the cube root sign
C = 6 There are no left overs.
Y secondFor the ys, you need 1 outside and 2 inside the root sign. that's because you need 5 altogether.
∛(y * y * y * y * y) = y ∛y^2
Answer c = 6; d = 2
Choice C <<<<<< answer
Answer:
v=2 s=5
Step-by-step explanation:
a) v=volleyball s=soccer
s × v = 7
" the soccer (s) practice lasts 1 hour (1) more than (+) twice as long (2) as the volleyball (v) practice; this simplifies to: s = 1 + 2v
b) substitute equation for soccer for s
(1 + 2v) + v = 7
solve for v
1 + 3v = 7 (2v + v = 3v; that's where the 3v comes from)
we subtract 1 from both sides
3v = 6
we divide 3 from both sides
v=2
solve for s
since we know what v equals, we substitute it in
s + 2 =7
subtract 2 from both sides
s = 5
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
Answer:
-1/8
Step-by-step explanation:
9-5(4-2)
--------------
3+5
First do the parentheses
9-5(2)
--------------
3+5
Then calculate the top and bottom of the fraction
We need to multiply and divide first
9-10
--------------
3+5
-1
--------------
8
The correct answer to the question is 1.4