The statement which best explains how the redox component of this reaction contributes to the reaction's ability to be reversible under cellular conditions is; <em>Choice D: The change in the biochemical standard reduction potential is small.</em>
Discussion:
A reversible process is one in which the system and environment can be restored to exactly the same initial states that they were in prior to when the process occurred, if we go backward along the path of the process.
- However, the necessary condition for a reversible process is therefore the quasi-static requirement.
- The quasi-static requirement in this case is that the change in the biochemical standard reduction potential is small.
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Answer:
Disulfide linkage/bond
Explanation:
The tertiary and quarternary structure of the protein is stabilized by Disulfide linkage which is formed between two thiol groups in the protein. 2-mercaptoethanol is a reducing agent that breaks this disulfide bond.
A protein becomes denature when it loses its native configuration and becomes inactive. So as 2-mercaptoethanol breaks disulfide bond in protein it looses its native configuration and becomes denatured. 2-mercaptoethanol is used in SDS-PAGE to separate protein subunits. Therefore the correct answer is Disulfide linkage/bond.
Living -
Respond to stimuli
Grow and develops
Used energy
Not living-
Non cellular
I am not sure about the reproduces only in a host cell. I would say living but I’m not 100% sure
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