<span>If set X is made up of the possible ways five students, represented by A, B, C, D, and E, can be formed into groups of three, then the set X consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, CDE} (note that triple ABC is the same as triple ACB, or BCA, or BAC, or CAB, or CBA). The set X totally contains 10 elements (triples). The first statement is true.
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<span>If set
Y is made up of the possible ways five students can be formed into
groups of three if student A must be in all possible groups, then </span><span>the set Y consists of such triples {ABC, ABD, ABE, ACD, ACE, ADE} and contains 6 elements. The second statement is also true.
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<span>If person E must be in each group, then there can be only one group is false statement, because you can see from the set X that triples which contains E are 6.
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<span>There are three ways to form a group if persons A and C must be in it. This statement is true and these groups are ABC, ACD, ACE.</span>
Answer:
2
Step-by-step explanation:
for the x-intercep put y=0 then you solve for x
To make it easier, remove the decimals, we'll add those later.
462
x 8
-------
3704
multiply each digit of 462 by 8. you get 3704.
now, since 46.3's decimal is one to the left and .8 is one to the left as well those are 2 place marks
so we move the decimal 2 places to the left in 3704, the answer
and we get 37.04
Answer:
75
Step-by-step explanation:
First divide 2/5 to get 0.4. Then divide 30 by 0.4 to get the answer. A simple way to think about it is how many 0.4 grams are in 30 gram tube.
