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3 years ago

PLSSSS HELP ME PLSSSSS

Mathematics

1 answer:

Yakvenalex [24]3 years ago

8 0

Answer:

1/27

Step-by-step explanation:

Ok this looks like a huge number but if you break it into smaller numbers its easier to work with

3^5=243 so we can write...

(3^5)^-3/5

Rule of exponents state that you can multiply powers

5*3/5=15/5=-3

Because its negative we would make it over 1

1/3^3

And simplify...

1/3*3*3

1/27

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Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base

suter [353]

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of m and n is:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

Exponent rule of division:

$a^{x}\div a^{y}=a^{x-y}$

Compute the value of the expression for m = -5 and n = 3 as follows:

$F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}$

$F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}$

$=\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}$

Thus, the correct option is option (3) 4 ÷ 25.

8 0

3 years ago

Read 2 more answers

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago

If xt = 3y -1 and us = 28, find the value of y

olga55 [171]

3y - 1 = 28
+ 1 + 1
----------------
3y = 29
---- ----
3 3
y= 9.66

8 0

3 years ago

What is the answer to question 10

Whitepunk [10]

He needs to earn ; 77.99-20= 57.99 dollars

so in one week there are 2 weekends; so he earns 6×3×2 = 36 dollars

so no of week = 57.99÷ 36= 1.6 weeks

so weeks are in natural no thus it will take him 2 weeks !!

8 0

3 years ago

Read 2 more answers

Part of the student's solution for finding the quotient 288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2 Which

Neporo4naja [7]

Answer:

A. 10 + 2

Step-by-step explanation:

288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2

After obtaining the quotient of 288 ÷ 24 = 10,

Multiplying the divisor 24 by 10 = 240 and subtracting 240 from 288 to obtain the remainder = 48, the divisor is again used in 48 and the quotient obtained is added to the intula quotient value of 10 ; (10 + 2) and the process repeated

6 0

2 years ago